Correct answer: Qc51...Ng3[a]/Nf2 2.N:g3#[A] 1...Qa3/Q:a1/Qa5/Qa8/[б]//Qc2 2.R:c4#[Б] 1...Nd5[c] 2.Qe6#[D] 1...Bd5[d] 2.Qf4#[F] 1...Be6[e]/B<