Correct answer: Bc21...Ne8[a]/Nb5[a]/Na6[a]/Na8[a] 2.Qe7#[C] 1...Rf3/Re4/h5 2.R3g5#[A] 1...Rf2/Rf1/Rh4 2.R3g5#[A]/Re3#[Б] 1...Rf5/Rg4/N<