Correct answer: Rc41...Bg3[a]/Qc5[d] 2.Kg2#[A] 1...Qf5+/Qe5/[б]//Qd5[c] 2.Ke3#[Б]/Kg2#[A] 1...Bf2/Bd2/Bc3/Bb4/Ba5 2.K:f2# 1.Rd4[C]? zz
