Correct answer: Qa31...Bd3[a]/Bd5/[б]//Bg3/[б]//Bh2/[б]//B:d6/[б]/ 2.Qd5#[A] 1...Bc6[c]/Bb7[c]/Ba8[c] 2.Qe5#[Б] 1...Bf5/Bg6/Bh7/Bc2/Bb1/B<