Correct answer: Be51...Ne3/Ne7/Ndf6/Ndc3/N:b4[a]/Nb6 2.Qf6#[A] 1...Nef6/[б]//Nec3/[б]/ 2.Qc3#[Б] 1.Kb8?? (2.Na7#) but 1...Nc5! 1.Be5! (2.<
