Correct answer: Qb81...Nd3 2.e:d3# 1.Qa7? (2.Qd4#[A]) 1...B:e2 2.Qe3# but 1...Nc2! 1.Qh8? (2.Qe5#[Б]/Qd4#[A]) 1...Nd3 2.Qd4#[A]/e:d3# 1...N
