Correct answer: Qd81...Bd5[a]/Be4/[б]//Bf3/Bg2/Bh1/Bd7[c]/Be8/Bd4[d] 2.Qb4#[A] 1...B:f2[e]/Bd6[f]/Be7/Bf8/Ba3 2.Q:b5#[Б] 1...b2 2.Qa2#