Correct answer: Ra41...Rc6[a]/c6 2.Qg5#[A] 1...c5/[б]/ 2.Qh1#[Б] 1...b4 2.Qc4# 1.Ra5? (2.Qc4#) 1...Rc6[a] 2.Qg5#[A] 1...c5/[б]/ 2.Qh1#[Б] but 1...f:e6! 1.Q