Correct answer: Bd51...R:c5[a] 2.R:f4#[Б] 1...g3 2.Nf3# 1...b:c4 2.Qd2#[A] 1...Bc3 2.Q:f4# 1...B:c4 2.Q:a1#[C] 1.f3? (2.Nb3#[D]) 1...R:c5[a] 2.R:f4#[Б]