Correct answer: Bc51...Kf3[a]/Qc1/Q:b1/Qe1/Q:c2/Ne2 2.R:g1#[A] 1...B:b1/Bd5/Rc4 2.Qd5# 1.Bb6? (2.Re2#) 1...Kf3[a] 2.R:g1#[A] 1..
