Correct answer: Qa21.Qg8? zz 1...Nb4[a]/Nc5[a]/Nc7[a] 2.Bc7#[A] 1...N:b8/[б]/ 2.Q:b8#[Б] 1...e3 2.Qg2# but 1...e5! 1.Qa2! zz 1...Nb4[a]/Nc5[