Correct answer: Qa61...Nc6[a] 2.Q:g8#[A] 1...Be6/[б]/ 2.Qc5#[Б] 1.Qa6! (2.Ne7#) 1...Nc6[a] 2.Qa2#[C] 1...Be6/[б]/ 2.Qb5#[D]
