Correct answer: Qh51...Nf3+[a] 2.Q:f3#[Б]/R:f3#[A] 1...Nf1/Nc4/Nb1/Nb3 2.Rf3#[A]/Q:f1#/Qf3#[Б] 1...Qb4/Qb3/Qb6/Qb7/Qc4/Qc6/Qd7/
