Correct answer: Qc31...Bd1/Be4[a]/B:b3[a] 2.Be4#[A] 1...Ra2/Raa1/R:a5/[б]/ 2.Rf3#[Б] 1...g4 2.Qf4# 1...Rba1 2.Rb5# 1.Qe3? (2.Qc5#) 1...B
