Correct answer: Qh71...Ne5[a] 2.N6e7#[A] 1...Nd6/[б]/ 2.N8e7#[Б] 1...K:c6 2.Q:e4# 1.Qh2? (2.N8e7#[Б]/N6e7#[A]) 1...Ne5[a] 2.N6e7#[A] 1...e3 2.Qh1#/