Correct answer: N:h61...Nc3[a]/Nd2 2.Nd2#[A] 1...Ng5/Nh8/Nd6/[б]//Nd8[c] 2.Nd6#[Б] 1...Rd3 2.Bb7# 1...Bc3 2.R:e3# 1.Ne1? (2.Bb7#) 1...
