Correct answer: Rb61.Rc5? (2.Rc1#) 1...Bb7[a] 2.Rgc6#[D] 1...Rb7/[б]/ 2.Rg7#[E] but 1...Rc7! 1.Rb5? (2.R:b2#) 1...Bb7[a] 2.Rc6#[A] 1...Rb7/