Correct answer: Qg11...K:c6[a] 2.Qd5#[A] 1...Ka8/[б]/ 2.Kc7#[Б] 1.Qg3? zz 1...K:c6[a] 2.Qc7#[C] 1...Ka8/[б]/ 2.Qb8#[D] but 1...Ka6! 1.Qf7? zz 1.
