Correct answer: Nb51...Nd7[a] 2.Q:b3#[A] 1...f6/[б]/ 2.Ng7#[Б] 1...N:d6 2.Re5# 1...f5 2.Rg6# 1...e:d6 2.Q:f7# 1.Nf4+[C]?? 1...Kf6 2.Rf5# but 1...K:d6!
