Correct answer: Rdf51...Be3[a] 2.R:e3#[A] 1...Nd4/[б]//Nd8/Ne5/Ne7/Nb4/Nb8/Na5/Na7 2.R:d4#[Б]/Re5#[C] 1...Nf6/Ng7/Nd6 2.N:f6# 1...
