Correct answer: Qf51...c4[a] 2.Q:c4#[A] 1...b5/[б]/ 2.Ra6#[Б] 1.Ra5? zz 1...c4[a] 2.Qd5#/Q:c4#[A] 1...b5/[б]/ 2.Ra6#[Б] 1...d5[c] 2.Qg6#[C] but 1...b:a5! 1.Rb4? zz