Correct answer: Rc41...Be5/Bg3[a]/Bh2[a]/Bc7/Bb8[a] 2.Ne7#[A] 1...Bf8/[б]//Bb4/Ba3/[б]/ 2.Nf4#[Б] 1...Bf4/Be7 2.N:f4#[Б]/Ne7#[A] 1...Bc5 2.