Correct answer: Qh81...Bd4[a] 2.Bd5#/Qa2#[A]/Qg8#[Б] 1.Qa5? (2.Qc3#) 1...Bd4[a] 2.Qa2#[A]/Q:b5#/Qb4#[C] 1...b4/[б]/ 2.Q:c5#[D] 1...Bb4[c] 2.Q