Correct answer: Rg31.Qg8? zz 1...f1Q[a]/f1R[a]/f1B/[б]/ 2.Qa2#[A] 1...f1N[c] 2.Qg2#[Б] but 1...Kf1! 1.Qf6? zz 1...f1Q[a]/f1R[a] 2.Qb2#[C] 1