Correct answer: Qd61...Qd4[a] 2.Ng3#[A] 1...Q:e5/[б]/ 2.Nd2#[Б] 1...Ng1/Nhf2/Nf4[c] 2.Qf4#[C] 1...Ne3[d]/Ndf2/Nc3/Nb2 2.Q:e3#[D] 1...f4 2.Qh7#/<
