Correct answer: Rd51...f3[a] 2.Qe3#[A] 1...Ne6/[б]//Nf3[c]/Nc2[d]/Nc6[d]/N:b3/[б]//Nb5[d] 2.Qf3#[Б] 1...Be5 2.R:e5# 1...Rg3/Rg2/R:g1/R:g5 2.Q