Correct answer: Qa81...Kc4[a] 2.Qe4#[A] 1.Qa1? zz 1...Kc4[a] 2.Qd4#[Б] 1...Ka5/[б]/ 2.Kb3#[C] but 1...Ka4! 1.Bb6?? (2.Qh4#/Qe4#[A]) 1...Kc4
