Correct answer: Bd21.Ke4[A]? zz 1...g6/[б]/ 2.Bd2#[Б] 1...Kg6 2.Kf4# but 1...h5[a]! 1.Kf3[C]? zz 1...h5[a] 2.Bd2#[Б] 1...Kh5 2.Kf4# but 1...g6/[б]/! 1.Bb
