Correct answer: Qc71...Nb6 2.B:e7# 1...Ng3/Nf2 2.Qf2# 1...e6 2.Qd6# 1.Qh4? (2.Q:e7#) 1...Bd3[a] 2.Qd4#[A] 1...B:b1/[б]/ 2.Q:c4#[Б] but 1...N