Correct answer: Qh71...Ne4[a] 2.e:d3#[A] 1...d:c2/[б]/ 2.e4#[Б] 1...d:e2+[c] 2.Q:e2#[C] 1...Nb4/Nc3 2.R:c1# 1...Nd7/Ne6/Nb3/Nb7/Na4/Na6 2.e:d3#[A]/e4#[Б] 1.R