Correct answer: Qb81...K:c5[a] 2.Qd6#[A] 1...d:c3/d3 2.Qf4# 1...b:c5 2.Qb8# 1.Qf4? (2.Q:d4#) 1...K:c5[a] 2.Qd6#[A] 1...b:c5 2.Qb8# but 1...B:d5! 1.Q