Correct answer: Qh21...Ne4[a]/f4[d] 2.Nf3#[Б] 1...Nd5/[б]/ 2.Nc6#[C] 1...e5/Ne5[c] 2.B:b6#[A] 1.Qh1? (2.Nc6#[C]) 1...Ne4[a] 2.Nf3#[Б] 1...Ne5[c] 2.B