Correct answer: Kb11...Kd2[a] 2.Qd1#[A] 1...Kd4/[б]/ 2.Qd5#[Б] 1.a5? zz 1...Kd2[a] 2.Qd1#[A] 1...Kd4/[б]/ 2.Qd5#[Б] but 1...b:a5! 1.Bc2+? 1...Kd2[a] 2.
