Correct answer: Qe51.Qe3? (2.Qb6#[A]) 1...R:c3 2.Q:c3# but 1...R:b5! 1.Qe7? (2.Qc7#[Б]/Qd8#[C]) 1...R:b5 2.Qa3# but 1...R:c3! 1.Qe8? (2.Q