Correct answer: Qb21...Kd5[a] 2.Q:a8#[A] 1...d5/[б]/ 2.Qc7#[Б] 1...Bb7+ 2.Q:b7# 1...c4 2.Qb5# 1.Kd8? zz 1...Kd5[a] 2.Q:a8#[A] 1...d5/[б]/ 2.Qc7#[Б] 1...c4