Correct answer: Bc51...Nf4[a]/Nf8[a]/Ng5[a]/Ng7[a]/Nd8[a]/Nc5/Nc7[a] 2.Nc7#[A] 1...Nb4/[б]//Nc1/[б]//Nc3/[б]/ 2.N:b4#[C] 1...c5 2.Qb7# 1...N:d4 2.
