Correct answer: c:b41...Nd5[a] 2.Be5#[C] 1...R:c8/[б]/ 2.B:c5#[D] 1...Bb3 2.c:b3# 1...Q:a4/b5 2.R:c5#[A] 1...Q:a6 2.R:c5#[A]/Q:b4#[Б] 1...Qc7 2.Q:b4#[Б] 1
