Correct answer: Bg41...Bd6[a] 2.B:c3#[A] 1.Qc6? (2.Nd7#[C]/B:c3#[A]) 1...Bd6[a] 2.Q:d6# 1...Nd5/[б]/ 2.Nd7#[C]/Q:d5# 1...Ra3/Rh4 2.Nd7#[C]
