Correct answer: Na51...Rc3[a] 2.N:d4#[A] 1...Bc3/[б]/ 2.Bd1#[Б] 1...Bc5 2.Qc4# 1.Qc4+?? 1...Bc3/[б]/ 2.Bd1#[Б]/Nd4#[A] but 1...R:c4! 1.Nc5?? (2.<
