Correct answer: Qc11...R:d3[a] 2.Qa4#[A] 1...e:d3/[б]/ 2.Qg4#[Б] 1.Qe1? (2.Q:e4#) 1...R:d3[a] 2.Qb4#[D] 1...e:d3/[б]/ 2.Qh4#/Qb4#[D] 1...K:d3[c] 2.Ndb4
