Correct answer: Qb71...K:e4[a] 2.Qg6#[A] 1...d:e4/[б]/ 2.O-O-O# 1.Qh5?? (2.Qe2#) 1...K:e4[a] 2.Bg6#[C]/Qg6#[A] but 1...K:c4! 1.Q:d5?? (2.O-O-O#) but 1...Kc2!