Correct answer: Bc31...Nc4[a]/Nc8/Na4 2.Ne6#[A] 1...d2/[б]/ 2.Be5#[Б]/Ne6#[A] 1...Rc8/Rb8/R:a8/Rde8/Nd5 2.N:d3# 1...Nd7 2.N:d3#/Ne6#[A]
