Correct answer: Qd11...Bd4[a] 2.Qg8#[A] 1...Bf8/[б]/ 2.Qh4#[Б] 1...Bg2/Bh3/Bd3 2.Qd3# 1...c:b5 2.Qd5# 1.Qd6? (2.Q:c5#) 1...Bd4[a] 2.Qe6#[C]
