Correct answer: Ncd81...d6[a] 2.Q:d6#[Б] 1...d:c6 2.B:f4#[A]/Qd6#[Б]/Qd8#/R:c6# 1.R:e7? (2.B:f4#[A]/Qd6#[Б]) 1...B:b7 2.Q:d7# but 1...B:e7! 1.Nca5[
