Correct answer: Qb11.Qe2? zz 1...d:c3+[a] 2.N:c3#[A] 1...d:e3+/[б]/ 2.K:e3#[C] 1...K:e4 2.Qg2# 1...d3 2.Q:d3# but 1...c4! 1.Qc2? zz 1...d:c3+[a] 2.K:c3#[D] 1
