Correct answer: Nc31...Nb4[a]/Nb8/[б]/ 2.B:b4#[A] 1...Nh8[c]/Nf4[d]/Nf8[c]/Ne7[e] 2.Bf4#[Б] 1.Be3? zz 1...Ke5/Nb4[a]/Nb8/[б]//Nc5 2.Bc5#[C]
