Correct answer: Rd21...Ng6/Nh7/Nd7 2.Nd7# 1.Rd8? (2.Bd6#[A]) 1...Nf3/[б]//Nc2[c]/N:c6/Nb3[c] 2.Rc2#[Б] 1...N:b5[d] 2.Nfd3#[C] 1...Nd
