Correct answer: Be41...Nh1[a]/Ngh5[a]/Nf1[a]/Nf5/[б]//Ne2[a]/Nge4 2.Nce2#[A] 1...Ng4[c]/Ng8[d]/Nfh5[d]/Nh7[d]/Nfe4/Ne8[d]/Nd5[d]/Nd7[d] 2.N<