Correct answer: Kc11...Qa6[a]/Qa7[a]/Qa8[a]/Qb4[c]/Qb6[a]/Qc7[a]/Qd8[d] 2.R3b4#[A] 1...Q:b5/[б]/ 2.Ra3#[Б] 1...Q:c3+ 2.N:c3# 1.Kd2? zz 1...Q