Correct answer: Ng71...Kd5[a] 2.Qf3#[A]/Qf5#[Б]/Q:d3#[C] 1.Bh5? (2.Qf3#[A]) 1...Kd5[a] 2.Qf5#[Б] but 1...g4! 1.Ra3? (2.Q:d3#[C]) 1...Kd5[a] 2.Qf
